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Java_Volume1 Complete Applications #99407

WebTest

So you have built a cool web site with code you wrote or downloaded from great sites like planet-source-code, the next thing you might want to do is testing it: Can your code handle more than, say 10 concurrent users? Does it have a memory leak that will eventually lead to crash if you don't reboot? Here is a java program I wrote that can query a web site continuously. If you want to simulate more than one user, just start as many instances of this program as you need. The command line to run it is: java WebTest "http://www.yahoo.com/" 20000 This will query the www.yahoo.com site continuously, sleeping a random amount of time from 0 up to 20000 milliseconds between consecutive requests. If you omit the second parameter, the default number 10000 will be used.

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Исходный код
original-source
import java.net.*; 
import java.io.*; 
import java.util.*; 
public class WebTest 
{ 
  public static void main (String[] args) 
  { 
    // initialize random seed 
    Random randomGen = new Random(new Date().getTime()); 
    while(true) 
    { 
      try 
      { 
        // sleep for a random interval 
        Thread.currentThread().sleep(randomGen.nextInt(args.length>1?(new Integer(args[1]).intValue()):10000)); 
        if(args.length>0) 
        { 
          // print the user supplied URL to the console window 
          System.out.println(args[0]); 
          // open URL connection 
          URLConnection urlConn = new URL(args[0]).openConnection(); 
          urlConn.setUseCaches(false); 
          // read and print the content to the console window 
          InputStream in = urlConn.getInputStream(); 
          byte buf[] = new byte[4096]; 
          int nSize = in.read(buf); 
          while(nSize>=0) 
          { 
            System.out.print(new String(buf,0,nSize)); 
            nSize = in.read(buf); 
          } 
          System.out.print("\r\n"); 
        } 
        else return; 
      } 
      catch(Exception e) 
      { 
        // print error message 
        System.out.println("Exception: "+e.getMessage()); 
      } 
    } 
  } 
} 

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